Topic 8 · ~8% of Regents exam · Mnemonic-driven

Oxidation-Reduction (Redox)

Redox is the chemistry of electron transfer. One substance loses electrons (oxidation), another gains them (reduction). Always at the same time. Together they power batteries, run corrosion, and underlie photosynthesis and respiration. The Regents tests two big mnemonics (LEO/GER and AN OX/RED CAT), oxidation numbers, half-reactions, and the difference between voltaic and electrolytic cells.

1. Oxidation numbers

An oxidation number (also called oxidation state) is the apparent charge an atom would have if all its bonds were ionic. It is a bookkeeping tool for tracking electrons.

Rules for assigning oxidation numbers

  1. An element by itself (Na, O₂, Cu, H₂) has an oxidation number of 0.
  2. A monatomic ion's oxidation number equals its charge: Na⁺ is +1, Cl⁻ is −1, Mg²⁺ is +2.
  3. Group 1 metals in compounds: always +1.
  4. Group 2 metals in compounds: always +2.
  5. Group 17 (halogens) in binary compounds with metals: −1.
  6. Hydrogen: usually +1 (but −1 in metal hydrides like NaH).
  7. Oxygen: usually −2 (but −1 in peroxides like H₂O₂).
  8. Sum of oxidation numbers in a neutral compound = 0.
  9. Sum of oxidation numbers in a polyatomic ion = the charge of the ion.

Worked example: nitrogen in HNO₃

Let N's oxidation number = x.

H: +1, each O: −2 (three of them = −6).
Sum: (+1) + x + (−6) = 0
x = +5

Nitrogen in nitric acid has an oxidation number of +5.

2. LEO the lion says GER

The most important mnemonic in redox

LEO = Lose Electrons = Oxidation
GER = Gain Electrons = Reduction

Picture a lion that says "Leo the lion says GER!" and you'll never forget it.

When an atom loses electrons, its oxidation number increases (becomes more positive). That's oxidation. When an atom gains electrons, its oxidation number decreases (becomes more negative). That's reduction.

ProcessElectronsOxidation numberExample
OxidationLostIncreasesMg → Mg²⁺ + 2e⁻ (0 → +2)
ReductionGainedDecreasesCl₂ + 2e⁻ → 2Cl⁻ (0 → −1)

Always paired

Oxidation and reduction always happen together. You can't have one without the other. Electrons don't appear or vanish; they move from one species to another. The species that loses electrons is being oxidized; the species that gains them is being reduced.

3. Oxidizing and reducing agents

The names trip people up. The oxidizing agent is the species that causes oxidation to happen. It does this by taking electrons, so it gets reduced. The opposite is true for the reducing agent.

AgentWhat it does to the other speciesWhat happens to itself
Oxidizing agentOxidizes it (takes its electrons)Gets reduced
Reducing agentReduces it (gives electrons to it)Gets oxidized

Pattern to remember

The substance being oxidized is the reducing agent. The substance being reduced is the oxidizing agent. They are opposites. If you see "Zn → Zn²⁺ + 2e⁻," Zn is being oxidized, so Zn is the reducing agent.

4. Half-reactions

A half-reaction shows just one half of a redox process: either oxidation or reduction by itself, with electrons explicitly written.

Example: Zn + Cu²⁺ → Zn²⁺ + Cu

Oxidation half-reaction: Zn → Zn²⁺ + 2e⁻

Reduction half-reaction: Cu²⁺ + 2e⁻ → Cu

In the oxidation half-reaction, electrons appear on the right (lost). In the reduction half-reaction, electrons appear on the left (gained). When you add the two halves and cancel electrons, you get the full redox equation.

5. Balancing redox equations

Half-reaction method (simple cases)

  1. Write the two half-reactions: one oxidation, one reduction.
  2. Balance the atoms in each half-reaction (other than H and O for now).
  3. Balance the charge in each half-reaction by adding electrons.
  4. Multiply each half-reaction so that the number of electrons lost equals the number gained.
  5. Add the two half-reactions and cancel anything that appears on both sides (including the electrons).

Worked example: aluminum + copper(II) ions

Skeleton: Al + Cu²⁺ → Al³⁺ + Cu

Oxidation: Al → Al³⁺ + 3e⁻ (Al loses 3 electrons)

Reduction: Cu²⁺ + 2e⁻ → Cu (Cu²⁺ gains 2 electrons)

Electrons lost (3) must equal electrons gained (2). LCM = 6. Multiply the oxidation by 2 and the reduction by 3:

Oxidation × 2: 2 Al → 2 Al³⁺ + 6e⁻

Reduction × 3: 3 Cu²⁺ + 6e⁻ → 3 Cu

Add and cancel the 6e⁻:

2 Al + 3 Cu²⁺ → 2 Al³⁺ + 3 Cu

6. Electrochemical cells

An electrochemical cell uses a redox reaction to interconvert chemical energy and electrical energy. There are two types: voltaic and electrolytic. Both share four parts:

  • Anode: the electrode where oxidation occurs.
  • Cathode: the electrode where reduction occurs.
  • External circuit: wires connecting the two electrodes; electrons flow through here.
  • Internal connection: a salt bridge (voltaic) or shared electrolyte (electrolytic) that allows ions to move to maintain charge balance.

AN OX, RED CAT

ANode = OXidation. REDuction = CAThode. Always true, in any cell. Picture an angry ox and a chill red cat.

Electron flow direction

In any electrochemical cell, electrons in the external circuit flow from the anode to the cathode. The current direction (by convention, positive charge) is opposite: cathode to anode in the external wire.

7. Voltaic cells (galvanic cells, batteries)

A voltaic cell uses a spontaneous redox reaction to produce electrical energy. Every battery you've used is a voltaic cell.

Spontaneous

The chemistry wants to happen on its own. No outside energy is needed.

Chemical → electrical

The cell converts chemical PE into electrical energy that can do work (light a bulb, run a motor).

Two separate compartments

The oxidation and reduction happen in separate half-cells connected by a salt bridge. Electrons travel through the external wire to do work.

Anode is negative (−)

Oxidation releases electrons there, so the anode has excess electrons. Counterintuitive but true. In voltaic cells: anode = (−), cathode = (+).

Classic example: zinc-copper voltaic cell

Zn(s) electrode in a Zn(NO₃)₂ solution; Cu(s) electrode in a Cu(NO₃)₂ solution; salt bridge between them; wire and bulb in the external circuit.

  • Zn is more active than Cu (see Table J), so Zn is oxidized at the anode: Zn → Zn²⁺ + 2e⁻
  • Cu²⁺ is reduced at the cathode: Cu²⁺ + 2e⁻ → Cu
  • Electrons flow through the external wire from Zn anode (−) to Cu cathode (+).
  • The Zn electrode loses mass; the Cu electrode gains mass.
  • The salt bridge allows ions to flow to keep both half-cells electrically neutral.

8. Electrolytic cells

An electrolytic cell uses electrical energy to drive a non-spontaneous redox reaction. Examples: electroplating, electrolysis of water, refining aluminum, recharging a battery.

FeatureVoltaic cellElectrolytic cell
ReactionSpontaneousNon-spontaneous (forced)
Energy flowChemical → electricalElectrical → chemical
Battery needed?No (cell IS the battery)Yes (needs power source)
Anode chargeNegative (−)Positive (+)
Cathode chargePositive (+)Negative (−)
Anode = oxidationYesYes (always)
Salt bridge?RequiredNot used; single container

Anode charge flips, but anode = oxidation always

In voltaic cells, the anode is negative. In electrolytic cells, the anode is positive. What stays constant in both: oxidation always happens at the anode, and reduction always happens at the cathode.

Common applications of electrolytic cells

  • Electroplating: coating a cheap metal with a thin layer of an expensive metal (silver-plated forks).
  • Electrolysis of water: 2 H₂O → 2 H₂ + O₂. Hydrogen at the cathode, oxygen at the anode.
  • Refining and producing metals: aluminum from bauxite via the Hall-Héroult process; copper purification.
  • Recharging a battery: forces the spontaneous reaction backward.

9. Activity series (Reference Table J)

Table J lists metals (and a separate list of halogens) in order of activity. More active = more easily oxidized = better reducing agent.

How to use Table J for single replacement reactions

A single replacement reaction has the form: A + BC → AC + B (where A and B are metals or halogens).

  • The reaction occurs if A is above B on Table J (A is more active and can displace B).
  • The reaction does not occur if A is below B (A is less active).

Worked examples

  • Zn + CuSO₄ → ZnSO₄ + Cu   (Zn is above Cu on Table J: reaction occurs)
  • Cu + ZnSO₄ → no reaction   (Cu is below Zn: cannot displace it)
  • Mg + 2 HCl → MgCl₂ + H₂   (Mg is above H₂: reaction occurs, gas bubbles off)

The "most active" metals

Lithium and the heavier alkali metals (K, Cs, Rb, Na) are at the top of Table J. They react violently with water. The least active metals (Au, Ag) sit at the bottom and resist corrosion: this is why gold and silver are used in jewelry and ancient artifacts are still recognizable.

Key terms

OxidationLoss of electrons. Oxidation number increases. "LEO."
ReductionGain of electrons. Oxidation number decreases. "GER."
Oxidation numberApparent charge of an atom if all bonds were ionic.
Oxidizing agentSpecies that causes oxidation. Itself gets reduced.
Reducing agentSpecies that causes reduction. Itself gets oxidized.
Half-reactionEither the oxidation or the reduction part, with electrons shown.
Redox reactionReaction involving electron transfer (change in oxidation numbers).
AnodeElectrode where oxidation occurs. Always. "AN OX."
CathodeElectrode where reduction occurs. Always. "RED CAT."
Voltaic cellUses spontaneous redox reaction to produce electricity. A battery.
Electrolytic cellUses electricity to drive a non-spontaneous reaction. Electroplating, electrolysis.
Salt bridgeAllows ions to flow between half-cells in a voltaic cell to maintain neutrality.

Practice questions

Q1. In the reaction 2 Na + Cl₂ → 2 NaCl, which species is oxidized?
  1. Na, because it loses electrons
  2. Na, because it gains electrons
  3. Cl₂, because it loses electrons
  4. Cl₂, because it gains electrons

Answer: (1) Na, because it loses electrons. Na goes from oxidation number 0 (elemental) to +1 (in NaCl). Its oxidation number increased, so it was oxidized. Cl₂ went from 0 to −1, gaining electrons (reduced). LEO: Lose Electrons, Oxidation.

Q2. Which statement correctly describes electron flow in a voltaic cell?
  1. Electrons flow from the cathode to the anode through the external circuit.
  2. Electrons flow from the anode to the cathode through the external circuit.
  3. Electrons flow through the salt bridge.
  4. Electrons remain stationary at the electrodes.

Answer: (2) Electrons flow from the anode to the cathode through the external circuit. Oxidation occurs at the anode, releasing electrons. They travel through the external wire to the cathode, where they are used in reduction. The salt bridge carries ions, not electrons.

Q3. Which of these reactions will occur, according to Reference Table J?
  1. Cu + 2 HCl → CuCl₂ + H₂
  2. Au + 2 HCl → AuCl₂ + H₂
  3. Mg + 2 HCl → MgCl₂ + H₂
  4. Ag + HCl → AgCl + ½ H₂

Answer: (3) Mg + 2 HCl → MgCl₂ + H₂. A single replacement reaction occurs when the metal is more active than (above) the one it's replacing on Table J. Magnesium is above hydrogen on Table J, so it can replace H. Copper, silver, and gold are all below hydrogen, so they don't react with dilute acids like HCl.

Q4. (Part B-2) Given the half-reactions: Cu²⁺ + 2e⁻ → Cu and Zn → Zn²⁺ + 2e⁻. Identify each as oxidation or reduction. Then combine them into a balanced net redox equation, showing your reasoning.

Sample full-credit response:
Half-reaction 1: Cu²⁺ + 2e⁻ → Cu. Cu²⁺ gains 2 electrons, going from oxidation number +2 to 0. This is reduction (GER: Gain Electrons, Reduction).

Half-reaction 2: Zn → Zn²⁺ + 2e⁻. Zn loses 2 electrons, going from oxidation number 0 to +2. This is oxidation (LEO: Lose Electrons, Oxidation).

Combining: Each half-reaction involves 2 electrons, so they already balance (2 lost = 2 gained). Adding them and canceling the electrons:
Zn + Cu²⁺ + 2e⁻ → Zn²⁺ + 2e⁻ + Cu
Cancel 2e⁻ on both sides:
Zn + Cu²⁺ → Zn²⁺ + Cu

Q5. (Part C) Compare voltaic cells and electrolytic cells. In your response, address (a) whether each uses a spontaneous or non-spontaneous redox reaction, (b) the direction of energy conversion in each, and (c) the charge of the anode in each type of cell. Give one real-world example of each.

Sample full-credit response:
(a) Spontaneity: A voltaic cell uses a spontaneous redox reaction; the chemistry happens on its own and releases energy. An electrolytic cell uses a non-spontaneous reaction; an external power source is needed to force the reaction to happen.

(b) Energy conversion: A voltaic cell converts chemical energy into electrical energy (it produces a current that can do work). An electrolytic cell converts electrical energy into chemical energy (it uses input electricity to drive a reaction that would not happen on its own).

(c) Anode charge: In a voltaic cell, the anode is negative because oxidation releases electrons there, building up negative charge. In an electrolytic cell, the anode is positive because the external power source pulls electrons away from it. In both cases, oxidation still occurs at the anode (AN OX is always true).

Examples: A voltaic cell is any common battery, such as an alkaline AA battery or a car's lead-acid battery. An electrolytic cell is used in electroplating silverware (silver from solution is deposited onto a base metal) and in the electrolysis of water to produce hydrogen gas.